If first, second and last terms are respectively a, b and 2a of an arithmetic progression, then prove that sum of progression will be
3ab 2(b- a)
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If first, second and last terms are respectively a, b and 2a of an arithmetic progression, then prove that sum of progression will be
3ab/ 2(b- a)
Step-by-step explanation:
First term = a, second term = b
Last term = 2a
∴common difference d = b - a
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