if first second and last terms of ap are a,b,2a then its sum will be
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Step-by-step explanation:
Answer of ur ques is- 3ab / 2(b-a)
A.P : a , b , . . . . . . . . . . . . . .2a
1st term= a1 = a
2nd term = a2= b
nth term = an = 2a
d = a2 - a1 = b-a
an = a1 + (n-1)d = a + (n-1)(b-a) = 2a
(n-1)(b-a) = a
(n-1) = a / (b-a)
n = a / (b-a) + 1 = b / ( b -a )
Sn = n / 2 * ( a1 + an) = b / 2(b-a) * ( a + 2a) = 3ab / 2(b-a)
Hope this helps! Cheers!!
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