If first term is 5 , 10th term is 23 , the sum of 10 terms is *
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Step-by-step explanation:
a = 5
n = 10
a10 = 23
a10 = a + ( n - 1 ) d
23 = 5 + ( 10 - 1 ) d
23 = 5 + 9 d
9d = 23 - 5
9d = 18
d = 18/9
d = 2
then we find sum of 10th term
sn = n / 2 ( a + an )
sn = 10/2 (5+ 23 )
sn = 5 (28)
sn = 140
i hope it help you
thank you !!
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