Question

if first term of an AP is -5 and common difference is 2
then find the sum of first 6 terms​

Answer 1

Answer:

refer to the attachment

Answer 2

Answer:

a1 = -5, d = 2 and n = 6

Sn = n/2[2a + (n-1)d]

= 6/2[2 × -5 + (6-1) × 2]

= 3[-10 + 5 × 2]

= 3 × [-10 + 10]

= 3 × 0 = 0

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