if fish cost 164and chips cost 134 and you went into the shop and asked for 2 fish and chips what would you be expecting to pay?
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Answer:
164+134 294 divide by 2 149 pay
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Let there be x rupees needed for fish , y for monkey and z for lion .
So according to conditions
40x+y+z=100
And
x+3y+5z = 100.
Now we have 3 unknown and 2 equation so we have to find solution by trial and error. We also know that x cannot be greater than 2 as than there will be 120 fish . so assuming x to be 2 we get y as 1 and z as 19 . So one possible solution is 80 fish , 1 monkey and 19 lions.
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