Question

If five resistances each of value 0.2 ohm are connected in series, what be the resultant resistance ?
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Answer 1

Answer:

Answer::-))

As per the law of combination of resistances in series,

R=R

1+R2+R3+R4+R5

R=0.2+0.2+0.2+0.2+0.2

=1ohm

Step-by-step explanation:

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Answer 2

Question:-

If five resistances each of value 0.2 ohm are connected in series, what be the resultant resistance ?

AnsWer :

1Ω.

To FinD :

• what be the resultant resistance ?

SolutioN :

Let,

• The Resistance be.
• R1 = 0.2.
• R2 = 0.2.
• R3 = 0.2.
• R4 = 0.2.
• R5 = 0.2.

✒ Condition :

• Given resistance connect in series combination.

▂▂▂▂▂▂▂▂

→ Rs = R1 + R2 + R3 + R4 + R5 ... Rn.

→ Rs = 0.2 + 0.2 + 0.2 + 0.2 + 0.2.

→ Rs = 1Ω.

▂▂▂▂▂▂▂▂

✎ Diagram :

----------( R1 )--( R2 )--( R3 )--( R4 )--( R5 )----------

✡ Therefore, the resultant resistance is 1 Ω.