If for a G.P, t₄ = 16 and t₉ = 512 then the first term and common ratio respectively are
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Since a =2, an =512 r=2 =>ar^n-1=512(2)2^n-1=512 ^n-1=256 =2^8n 1=8n= 9 now r^th trem from last = (n-r+1) ^th trem from staing
=>5 term from last =(9-5+1)th 5th term from staing
=>an=ar n-1 =>a5 =(2) (2) 5-1 =25 =32
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