If for an A.P. a=10 d=3 then find S=15
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3
Answer:
Given a=10,d=3,
S15 = n/2 [2a+(n-1)d]
= 15/2[2x10+(15-1 ) x3]
= 15/2[20+14x3]
= 15/2[20+42]
= 15/2[62]
= 15x31
= 465
Answered by
0
Answer:
465
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