If for an A.P. a=3,d=6 then find Sn and hence find S10
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Answered by
10
Sn = n/2(6 +[n -1]6)
=n/2[6 + 6n-6]
=n/2[6n]
=3nsquare!
S10=10/2[6+(9)6]
=10/2[60]
=10[30]
=300!
=n/2[6 + 6n-6]
=n/2[6n]
=3nsquare!
S10=10/2[6+(9)6]
=10/2[60]
=10[30]
=300!
Answered by
8
Hello here is your answer
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