If for an A.P d = 11, what is t17- t15 ?
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Answer:
Step-by-step explanation:
Given that,
Common difference=d=11
first term=a=a
number of the term=n
T
n
=a+(n−1)d
T
17
=a+(17−1)11
=a+(16)11
=a+176
T
n
=a+(n−1)d
T
15
=a+(15−1)11
=a+(14)11
=a+154
then,
T
17
−T
15
=(a+176)−(a+154)
=a+176−a−154
=22
Thus,
We get A.P=22
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