if for an A.P. , d = 20 , what is the value of t6 - t2
Answers
Answered by
0
Answer:
Correct option is
A
40
In an A.P,d=10 then,
t
6
−t
2
=(a+5d)−(a+d)
=a+5d−a−d
=4d=4×10
=40 (Ans)
Answered by
4
Answer:
t6-t2=80
Step-by-step explanation:
tn-(tn-1)=d for any natural number n
t6-t5=d=20 -(1)
t5-t4=d=20 -(2)
t4-t3=d=20 -(3)
t3-t2=d=20 -(4)
Adding (1), (2), (3) and 4
t6-t5+t5-t4+t4-t3+t3-t2=d+d+d+d=20+20+20+20
t6-t2=4d=80
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