Question

if for an A.P.d=5 then t18=?​

Answer 1

Answer:

It is given that,

d=5

Now,

tn=a+(n−1)d

t18−t13=(a+(18−1)d)−(a+(13−1)d)

(a+17d)−(a+12d)

=5d

=5(5)

=25

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