Math, asked by dhruvijadav60, 7 months ago

If for an A.P S₃₁=2604 find the 16th term.


AestheticSky: but in this question the value of a and d is not provided !
AestheticSky: I think ur question is incomplete

Answers

Answered by siddhant11996
1

Step-by-step explanation:

HOPE IT HELPS YOU

PLEASE MARK ME AS BRAINLIEST

Attachments:
Answered by AestheticSky
18

Given:-

\sf S_{31} = 2604

To find:-

  • 16th term.

Formula:-

\underline{\boxed{\sf S = \dfrac{n}{2} × 2a+(n-1)d}}

here,

  • \sf S_{31} = sum of the terms
  • a = 1st term
  • n = no. of terms
  • d = common difference

Solution:-

\longrightarrow 2604 = \sf\dfrac{31}{2} × 2a+30d

\longrightarrow \sf\dfrac{2604×2}{31} = 2a+30d

\longrightarrow 168 = 2a+30d

\longrightarrow 84 = a+15d

Now,

\sf a_{16} = a+15d

hence, the value of 16th term is 84

Additional information:-

to find the value of a term i.e \sf a_{n}, following formula is used:-

\underline{\boxed{\sf a_{n} = a+(n-1)d}}

here,

  • \sf a_{n} = nth term
  • a = 1st term
  • n = no. of term
  • d = common difference
Similar questions