If, for an A.P., S33=198, then t17 is
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1
Answer:
6
Step-by-step explanation:
S=n/2(2a+(n-1) d)
S33=198
S33=33/2(2a+(33-1)d)
198=33/2(2a+32d)
198=33(a+16d)
198/33=a+16d
6=a +16d
a+16d=t17
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