If for an A.P S51=7650,find the 26th term
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Hi ,
Let a and d are first term and
common difference of an A.P
We know that ,
n the term of an A.P = an
an = a + ( n - 1 )d
a26 = a + ( 26 - 1 ) d
a26 = a + 25d ------( 1 )
Sum of n terms an A.P = Sn
Sn = n /2 [ 2a + ( n - 1 )d ]
S51 = 7650 ( given )
51/2 [ 2a + ( 51 - 1 )d ] = 7650
51 /2 [ 2a + 50d] = 7650
( 51 / 2 ) × 2 [ a + 25d ] = 7650
51 [ a + 25d ] = 7650
a + 25d = 7650 / 51
a + 25d = ( 51 × 150 ) / 51
a + 25d = 150
a26 = 150 [ from ( 1 ) ]
26 th term in given A.P = a26 = 150
I hope this helps you.
:)
Let a and d are first term and
common difference of an A.P
We know that ,
n the term of an A.P = an
an = a + ( n - 1 )d
a26 = a + ( 26 - 1 ) d
a26 = a + 25d ------( 1 )
Sum of n terms an A.P = Sn
Sn = n /2 [ 2a + ( n - 1 )d ]
S51 = 7650 ( given )
51/2 [ 2a + ( 51 - 1 )d ] = 7650
51 /2 [ 2a + 50d] = 7650
( 51 / 2 ) × 2 [ a + 25d ] = 7650
51 [ a + 25d ] = 7650
a + 25d = 7650 / 51
a + 25d = ( 51 × 150 ) / 51
a + 25d = 150
a26 = 150 [ from ( 1 ) ]
26 th term in given A.P = a26 = 150
I hope this helps you.
:)
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