If for an A.P the first term is 7 and the common difference is (-2) then find Sn and hence find S8
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a=7
d= -2
sn=?
sn= n/2 ( 2a +(n-1)d)
sn= n/2 ( 2(7)+(n-1)(-2))
sn= n/2 (14 -2n+2)
sn= n/2 (16-2n)
sn= n/2 [2(8-n)]
sn= n(8-n)
sn= -n^2 +8n
S8= 8/2 [2(7)+(8-1)(-2)]
S8= 4 [14+(7)(-2)]
S8= 4 [14-14]
S8= 4(0)
S8=0
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