If for any function f:R→R,f(a+b)=f(a)+f(b) for all a and b, then f(0) is
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ANSWER ::
For the function f:R→R
f(a+b)=f(a)+f(b) for all a and b
Putting a=b=0 we get
f(0) = f(0) + f(0)
∴ f(0) = 0
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