if for ax²+bx+c=0,b²-4ac<0 the root of the quadratic equation options1. real and equal 2.complex conjugate 3.real and unequal 4.none of abov
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Tf how tough
4-5
1111.334
4-5
1111.334
Answered by
2
Answer:
Complex Conjugate
Step-by-step explanation:
b²-4ac < 0 , therefore, D = -(b²-4ac)
√D = √-(b²-4ac) = i√(b²-4ac)
where i is complex
therefore, roots are complex Conjugate
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