If for G.P,S3=125,S6=152,find r
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1
Answer:
S
3
=125,S
6
=152
S=
r−1
a(r
n
−1)
S
3
=
2
a(r
3
−1)
=125⟹a(r
3
−1)=250
S
6
=
5
a(r
6
−1)
=152⟹a(r
6
−1)=760
a(r
6
−1)=760
a(r
3
−1)(r
3
+1)=760
(r
3
+1)=
250
760
r
3
=
25
76
−1
r=1.268
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