if for numbers LCm =180 ,HCF = 6 and one nunber is 30 , then find the other number
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Given,
LCM = 180
HCF = 6
1st number = 30
Let 2nd number be x.
LCM × HCF = 1st number × 2nd number
180 × 6 = 30 × x
1080 = 30 × x
x = 1080÷30
x = 36 And
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