Question

If for some function h given by h(x)=kx*2+7x-4, h'(5)=97 , find k

Answer 1

Given that,
h(x) = kx² + 7x - 4

Now, differentiating both the sides with respect to x, we get
h'(x) = 2kx + 7

Given that,
h'(5) = 97
or, 2k (5) = 97
or, 10k = 97
or, k = $\frac{97}{10}$
or, k = 9.7

Hence, k = 9.7

Answer 2

Answer:

Step-by-step explanation:

Kx^2+7x-4=h(x)

putting x=5

K*5^2+7*5-4=97

25k=97-35+4=66

K=66/25