Math, asked by nickyrocker03, 9 months ago

if for two independent events A and B , P(AuB) = 2/3 and P(A)=2/5 what is P(B)?​

Answers

Answered by ayushirajibdas05
68

Answer:

P(B) = 4/9

Step-by-step explanation:

For Independent events:-

P(A Intersection B) = P(A).P(B)..........{i}

Now, P(AUB) = P(A) + P(B) - P( A Intersection B)

= P(A) + P(B) - P(A).P(B).......{From i}

2/3 = 2/5 + P(B) - 2/5.P(B)

2/3 - 2/5 = P(B) (1 -2/5)....{Taking P(B) common}

4/15 = P(B) (5 - 2/5)

4/15 = P(B) (3/5)

4/15 × 5/3 = P(B)

4/9 = P(B)......{ Required Answer}

HOPE THIS HELPS!

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