If for two numbers mean is 25 and hm is 9 find gm
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let the numbers be a and b then
arthimatic mean= a+b/2
a+b/2=15 , a+b=30 , a=30-b -----------(1)
geometric mean: sqr(a.b)
sqr(a.b)=9--------------(2)
from equation 2 by replacing a by 30-b
sqr{b(30-b)}=9
by squaring both side of the equation
30b-b2=81
B2-30b+81=0
B2-3b-27b+81=0
B(b-3)-27(b-3)_=0
(b-3)(b-27)=0
B=3 ,b=27
If b=3 , then a=30-b =30-3=27
,bu if
B=27, then a=30-b=30-27=3
Therefore , the numbers are 3 and 27
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