Question

if for two vectors A and B sum (A+B) is perpendicular to the difference (A-B) the ratio of their magnitude is??? ​

Answer 1

Hii

you are welcome in my ans

(A+B).(A-B) =( A+B)(A-B)cos90

A^2 - B^2 = 0

A/B =1

so ans is 1

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Hope it may helps you

Answer 2

Answer:

1

Explanation:

Given that

A and B  are two vector

A+B and A-B are perpendicular to each other.

We know that if two vectors(M and N) are perpendicular to each other then

M . N = |M|. |N| cos θ

Perpendicular θ =90°

  so cos 90° = 0

M . N = |M|. |N| cos θ = |M|. |N| x 0

M . N = 0

So we can say that

( A+B  ).(A-B ) = 0

A.A+B.A- A.B - B.B = 0            ( A.B=B.A)

A.A - B.B=0                          

So we can say that

|A| = |B|

So ratio of their magnitude is 1.