Question

If force F = 50 - 20t, then impulse in interval (0, 1) is
(1) 50t-10t^2
(2) 50t -10
(3) 50-t^2
(4) 25t^2​

Answer 1

Given :-

F = 50 - 20t

As we know that,

Impulse is the product of force and time.

Here, in this question we are required to integrate Force w.r.t time.

$\int{dI} = \int{F\:dt}$

$I\: = \int{50 - 20t\:dt}$

$I\: = {[50t - \dfrac{20{t}^{2}}{2}]}_{0}^{2}$

I = 50t - 10t².

Hence,

The impulse = I = 50t - 10t².

Answer 2

Explanation:

hope you got it thank you