If force (F) acceleration (A) and time (T) are taken as fundamental units, then find the dimension of energy.
CLASS - XI PHYSICS (Physical World & Measurement)
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[ F ] = [ M ] [ L ] [ T ]⁻²
[ A ] = [ L ] [ T ]⁻²
T = T
Energy = Work = Force * displacement
= [ M ] [ L ]² [ T ]⁻² = [ F ]^a [ A ]^b [ T ]^c
Power of [ M ] = 1 => a = 1
power of [ L ] = a+b = 2 => b = 1
Power of [ T ] = -2 = -2a -2b + c => c = 2
So energy = [ F ] [ A ] [ T ]²
[ A ] = [ L ] [ T ]⁻²
T = T
Energy = Work = Force * displacement
= [ M ] [ L ]² [ T ]⁻² = [ F ]^a [ A ]^b [ T ]^c
Power of [ M ] = 1 => a = 1
power of [ L ] = a+b = 2 => b = 1
Power of [ T ] = -2 = -2a -2b + c => c = 2
So energy = [ F ] [ A ] [ T ]²
Answered by
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Explanation:[ F ] = [ M ] [ L ] [ T ]⁻²
[ A ] = [ L ] [ T ]⁻²
T = T
Energy = Work = Force * displacement
= [ M ] [ L ]² [ T ]⁻² = [ F ]^a [ A ]^b [ T ]^c
Power of [ M ] = 1 => a = 1
power of [ L ] = a+b = 2 => b = 1
Power of [ T ] = -2 = -2a -2b + c => c = 2
So energy = [ F ] [ A ] [ T ]²
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