Question

. If force (F), acceleration (A) and time (T) be taken as the
fundamental physical quantities, the dimensions of length
on this system of units are​

Answer 1

Answer:

Force =F=[MLT

−2

]

acceleration =A=[LT

−2

]

time =T=[T]

length =L

L=F

x

A

y

T

z

[L]=[MLT

−2

]

x

[LT

−2

]

y

[T]

z

[M

0

LT

0

]=[M

x

L

x+y

T

−2x−2y+z

]

Comparing both sides,

x=0 x+y=1

y=1

−2x−2y+z=0

0−2×1+z=0

z=2

Length =F

0

A

1

T

2

L=[F

0

AT

2

]=[AT

2

]

Explanation:

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