If force on one charge of a dipole due to the second is 0.2N towards right, what is the force on the second charge due to the first and in which direction?
Answers
Answer:
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Explanation:
Let's first consider a dipole consisting of 2 equal charges placed at small distance from each other.
So According to Electrostatics Force Theorem , the magnitude of force will be :
F = \dfrac{1}{4\pi \epsilon_{0}} \dfrac{ {q}^{2} }{ {d}^{2} }F=
4πϵ
0
1
d
2
q
2
As per the question , we see :
F = \dfrac{1}{4\pi \epsilon_{0}} \dfrac{ {q}^{2} }{ {d}^{2} } = 0.2 \: NF=
4πϵ
0
1
d
2
q
2
=0.2N
Now , it has also been mentioned that : Force of one charge on the dipole due to the other charge is directed rightwards.
This is possible only in 1 case :
Positive charge on left side and negative charge on right side .
Let the positive charge experience 0.2 N force rightwards due to Negative .
Similarly the negative charge will also experience 0.2 N charge towards the right side.
Refer to the attached diagram.
