if force = x/area +y is dimensionally correct, the dimensions of xy are
1. [M^2L^4T^-2]
2. [ML^3T^-4]
3. [ML^2T^-2]
4. [M^0L^3T^-4]
Answers
Answered by
1
Answer:
The above Answer is. 4) [M^0L^3T^-4]
Explanation:
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Answered by
1
Answer:
the force = 5T(66>ΔHSNN611
C6880^T55=629999$5 -66= 58
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