Question

if formula for a physical quantity is W =a^4*b^3/c^2*√D and if percentage error in the measurement of a,b,c&d are 1%,2%,3%&4% respectively. find the percentage error in W​

Answer 1

Answer:

Percentage error in W = 18%

Explanation:

W = a⁴ * b³ / c² * √d

ΔW / W = 4Δa/a + 3Δb/b + 2Δc/c + 1/2 Δd/d

Where,

Δa/a = % error in a = 1%

Δb/b = % error in b = 2%

Δc/c = % error in c = 3%

Δd/d = % error in d = 4%

ΔW/W = % error in W = ?

Putting these values in we get,

ΔW/W = 4*1 + 3*2 + 2*3 + 1/2 * 4

ΔW/W = 4 + 6 + 6 + 2

ΔW/W = 18%

Answer 2

Answer:

18

Explanation:

18 will be your answer