If four dice are thrown together, then the probability that the sum of the number
appearing on them is 13, is
1) 5/216
2) 11/216
3) 35/324
4) 11/432
Answers
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2
since n(S)=6
4
=1296 and permutation that the sum of the numbers appearing on them is 13.
Total permutation of (1,1,5,6)=
2!
4!
=12
Total permutation of (1,2,4,6)=4!=24
Similarly for (1,3,3,6)=
2!
4!
=12
(1,2,5,5)=12;(1,3,5,4)=24;(2,2,6,3)=12;(2,2,5,4)=12;
(3,3,2,5)=12;(3,3,3,4)=4;(4,4,4,1)=4and4,4,3,2)=12
∴ Required probability
=
1296
12+24+12+12+24+12+12+12+4+4+12
=
1296
140
=
324
35
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