if four healthy plants of the same type are selected and put inside bell jars and their details are as follows:
plant 1-light with sodium hydroxide
plant 2-under shade with sodium hydroxide
plant 3-light with sodium bicarbonate
plant 4-under shade with sodium bicarbonate
and sodium hydroxide (soda lime) absorbs carbon dioxide
and sodium bicarbonate releases carbon dioxide
After a week a leaf from each plant is tested with iodine. state the outcome you would expect from testing a leaf from each plant with iodine i.e. red/brown or blue/black.PLZZZZZ ANSWER QUICK.FIRST PERSON WILL BE GIVEN BRAINLIEST
Answers
Take two healthy potted plants which are nearly the same size. Keep them in a dark room for three days. Now place each plant on separate glass plates. Place a watch-glass containing potassium hydroxide by the side of one of the plants. The potassium hydroxide is used to absorb carbon dioxide. Cover both plants with separate bell-jars. Use Vaseline to seal the bottom of the jars to the glass plates so that the set-up is air-tight. Keep the plants in sunlight for about two hours. Pluck a leaf from each plant. Remove the green coloured chlorophyll from the leaves by boiling them in alcohol. Wash the decolourised leaves with water and then pour iodine solution over them. Observe the change in colour of the leaves. We will find that the leaf from the plant (which was inside the bell jar containing potassium hydroxide which absorbed the carbon dioxide), does not turn blue-black on adding iodine solution showing that no starch is present. So we can conclude that the photosynthesis cannot be carried out without carbon dioxide.
hope it's helpful
plsssss mark brainliest......