Question

if four horizontal forces F1=3N F2=6N F3=3N AND F4=6N is applied on a body of mass 5 kg. If force F3 is removed ,then find the value of rate of change of momentum.

Answer 1

The rate of change of momentum is 3 kg-m/s²

Explanation:

The horizontal forces as

$F_1=3$ N

$F_2=6$ N

$F_3=3$ N

$F_4=6$ N

If $F_3$ is removed

Then there will be change in momentum

From Newton's second law we know that

Rate of change of momentum = Force

$F=\frac{d}{dt}(mv)$

$\implies F=\frac{m(v_2-v_1)}{t}$

Since force of 3 N is removed

Therefore, rate of change of momentum = 3 kg-m/s²

Hope this answer is helpful.

Know More:

Q: The rate change of momentum of a body is 5 kilogram metre per second what is the force acting on the body?

Click Here: https://brainly.in/question/5776813

Q: If change in momentum in 0.01s is 10kg m/s. Find the force acting on a body?

Click Here: https://brainly.in/question/1491567