Question

if four number in ap are such that their sum is 50 and thegreatest number 4 times the least , then find the numders.​

Answer 1

Answer:

Here, we are given that four numbers are in A.P., such that their sum is 50 and the greatest number is 4 times the smallest. So, let us take the four terms as a - d , a , a + d , a + 2d. Therefore, the four terms are 5, 10 , 15, 20.

Step-by-step explanation:

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Answer 2

Answer:

5,10,15,20

Step-by-step explanation:

Let the numbers be a−3d,a−d,a+d,a+3d

Given, sum of all the numbers:

a−3d+a−d+a+d+a+3d=50

4a=50

a=12.5

Given,

largest number = 4 (smallest number)

a+3d=4a−12d

15d=3a

a=5d

d=

5

12.5

=2.5

Therefore, numbers are 5,10,15,20.