Question

If four numbers A1 A2 A3 and A4 are inserted between the numbers 4 and 19 such that 4, A1 A2 A3 A4 19 is an A.P, then what is the value of the expression A1 + A2 + A3 + A4?

a) 36 b) 40 c) 46 d) 50​

Answer 1

Answer:

A1 + A2 + A3 + A4 = 46

Step-by-step explanation:

To find the number of number we subtract 4 from 19 then add one to get 16 numbers between 4 and 19 inclusive.

So, we get

4, 7, 10, 13, 16, 19

So,

A1 + A2 + A3 + A4 = 46

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Answer 2

Answer:

c) 46

Step-by-step explanation:

a = 4

a6 = 19

n = 6

an = a + (n-1)d

19 = a + 5d

19 = 4 + 5d

5d = 15

d = 3

a1 = 4

a2 = a + d = 7

a3 = a + 2d = 10

a4 = a + 3d = 13

a5 = a + 4d = 16

a6 = 19

A1 + A2 + A3 + A4 = 7 + 10 + 13 + 16 = 46

Hope it helps you:)