If four numbers in A.P. are such that their sum is 50 and the greatest number is 4 times the least, then the numbers are
A. 5, 10, 15, 20
B. 4, 10, 16, 22
C. 3, 7, 11, 15
D. none of these
Answers
Answered by
1
Answer:
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Answered by
5
A. 5, 10, 15, 20
Step-by-step explanation:
Given: If four numbers in A.P. are such that their sum is 50 and the greatest number is 4 times the least
Solution:
n = 4
S4 = 50
4a = L
S4 = 4/2 (a + L)
50 = 2 (a + 4a)
50 = 2(5a)
Therefore a = 50/10 = 5.
L = 4a = 20.
L = a + 3d = 5 + 3d = 20
3d = 15
Therefore d = 5.
So the AP will be 5, 10, 15, 20
Option A is the answer.
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