Question

if four terms in ap are such that thier sum is 50,and greatest numbers is 4 times the least,then numbers are ?​

Answer 1

Step-by-step explanation:

let the four in ap be= a-3d, a-d, a+d, a+3d

then a-3d + a-d + a+d + a+3d

4a=50

a=50/4=25/2

we are find the greatest number is four times the least number

a+3d = 4(a-3d)

a+3d = 4a-12d

-3a = -15d

5d = 25/2= 5d = d= 25/2*5 = 5/2

we are find four number in ap.

a-3d , a-d , a+d , a+3d

25/2 - 3(5/2) , 25/2-5/2 , 25/2+5/2 , 25/2 +3(5/2)

25/2 - 15/2 , 25/2 - 5/2 , 25/2 + 5/2 , 25/2 +15/2

10/2 , 20/2 , 30/2 , 40/2

(5 , 10 , 15 , 20) is our answer

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