if four times the fourth term of an ap is equal to 7 times its 7th term find its 11th term
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4(a_4) = 7(a_7)
4(a + 3d) = 7(a + 6d)
4a + 12d = 7a + 42d
7a - 4a + 42d - 12d = 0
3a + 30d = 0
3(a + 10d) = 0
a + 10d = 0
a_11 = 0
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