if fourth term of Hp is 3/4 and seventh term of HP is 2/3. find the tenth term
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Given ,
1/(a + 3d) = 3/4. and. 1/(a + 6d) = 2/3
=> (a + 3d) = 4/3. &. (a + 6d) = 3/2
so, (by eq.2 - eq.1 we get)
3d = (3/2 - 4/3)
=> d = (9 - 8)/18
=> d = 1/18
put value in equation 1
a = (4/3 - 3/18)
=> a = (4/3 - 1/6)
=> a = (8-1)/6 = 7/6
now,
= (a + 9d)
= (7/6 + 9/18)
= (7/6 + 1/2)
= (7+3)/6
= 10/6
= 5/3
so, 1/(a + 9d) = 3/5
The tenth term is = 3/5 (ans)
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