if fourth term of the gp is 40 and 10th term is 2560. find gp
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0
It's 5,10,20,40,80,160,320,640,1280,2560
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a4 = 40, a10= 2560
formula an = a×r^(n-1)
a4= a×r^(4-1)
a4= a×r³ = 40......(1)
a10 = a×r^(10-1)
a10= a×r^9 = 2560......(2)
divide (2) by (1)
r^9/r³ = 2560/40
r³ = 64
r³ = 4³
r= 4
put this value in (1)
we get:-
a= 5/8
so, GP is
5/8,5/2,10,40,.......
NeelamG:
i hope it will help u
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