if frequency of A tuning fork is 256 hertz how many oscillation will executed by it in 10 second
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answer will be 2560 oscillation
chiragverma:
m I right
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f = 1/T
so, T = 1/f
= 1/256
=0.0039 or 0.004 sec
Time period is time taken for 1 oscillation.
Since, time period is 0.004 sec
So in 10 secs. no. of oscillations = 2500.
so, T = 1/f
= 1/256
=0.0039 or 0.004 sec
Time period is time taken for 1 oscillation.
Since, time period is 0.004 sec
So in 10 secs. no. of oscillations = 2500.
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