If frequency of allele is 0.2 what is the frequency of heterozygous
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The frequency of heterozygous individuals is equal to 2pq. In this case, 2pq equals 0.32, which means that the frequency of individuals heterozygous for this gene is equal to 32% (i.e. 2 (0.8)(0.2) =0.32).
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The frequency formula in terms of time is given as: f = 1/T where, f is the frequency in hertz, and T is the time to complete one cycle in seconds. The frequency formula in terms of wavelength and wave speed is given as, f = /λ where, is the wave speed, and λ is the wavelength of the wave.
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