Question

If frequency of the X rays produced using an element as anti cathode is found to be 2500 sec^1 , the atomic number of used element is (if a=b=1)
(a)51
(b)49
(c)56
(d)72

Answer 1

Answer:

the correct answer is (a) 51

Explanation:

√v=a(Z-b)

√2500 =1(Z-1)=Z=50+1=51

Answer 2

Answer:

C. The correct option is c. Do you understood that