Question

If from an external point of a circle with centre O, two tangents BC and BD are drawn such that < DBC = 120° then prove that BO = 2 BC

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Answer 1

Answer:

obc = angle obd=60

In triangle obc cos 60 =bc/ob

1/2 bc/ob

ob = 2bc

Answer 2

Step-by-step explanation:

obc =angle obd =60

in triangle obc cos =60 =bc /ob

1/2 bc/ob

ob =2bc

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