if from an external point p of a circle with centreo , two tangents PQ & PR are drawn such that angle QPR =120 , prove that 2PQ = PO
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∠QPR = 120°
PQ = PR
∠QPR + ∠QOR = 180°
∠QOR = 60°
IN ΔOPQ
∠QOP = 30° [ OP BISECTS THE ANGLE ]
SIN 30 = PQ/OP
1/2 = PQ / OP
2PQ = OP
H.P.
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