If from an external point T two tangents TP and TQ are drawn to a circle with center O.
prove that OT ia right bisector of segment PQ.
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Step-by-step explanation:
TP = TQ (Lengths of tangents drawn from an external point to a circle are equal.) Now, in ∆PRT and ∆QRT, TP = TQ (Lengths of tangents drawn from an external point to a circle are equal.) OT is the right bisector of the line segment PQ.
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