If from external point P of a circle with centre O , two tangents PQ and PR are drawn such that angle QPR is 120° , prove that 2PQ = PO
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by theorem angle opq nd angle opr is 60 degree... now in triangle opq nd OPR cos 60 degree= PQ/OP nd PR/OP respectively..
add both these equation so we get PQ+PR/OP nd we know that tangents r equal so 2PQ= OP
add both these equation so we get PQ+PR/OP nd we know that tangents r equal so 2PQ= OP
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