If from twice the greater of two numbers 16 is subtracted, the result is half the other
number. If from half the greater number 1 is subtracted, the result is still half the other
number. What are the numbers
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Let’s consider the greater number to be x and the smaller number to be y.
Then, according to the given conditions we have
2x–16=
2
y
⇒4x−32=y⇒4x−y=32 … (i)
And,
2
x
−1=
2
y
⇒x−2=y⇒x−y=2 … (ii)
Now, subtracting (ii) from (i) we get
(4x−y)−(x−y)=32−2
⇒3x=30
⇒x=10
On substituting the value of x in (i), we get
2(10)−16=
2
y
⇒20−16=
2
y
⇒4=
2
y
⇒y=8
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