Question

if from twice the greater of two positive numbers 16 is subtracted, the result is half the other. if from half the greater number, 1 is subtracted, result is still half the other number. find the numbers.
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Answer 1

Hey!!!

__________

Refer to the attachments

The two numbers are 10 and 8.

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Hope this helps

Answer 2

Answer:

10 , 8

Step-by-step explanation:

Given : if from twice the greater of two positive numbers 16 is subtracted, the result is half the other. if from half the greater number, 1 is subtracted, result is still half the other number.

To Find:  find the numbers.

Solution:

let greater number be x

Let smaller number be y

Since we are given that f from twice the greater of two positive numbers 16 is subtracted, the result is half the other.

⇒$2x-16=\frac{y}{2}$

⇒$4x-32=y$  --a

Since we are also given that  if from half the greater number, 1 is subtracted, result is still half the other number.

⇒$\frac{x}{2} -1 = \frac{y}{2}$

⇒$x-2=y$ --b

Now solve a and b

Substitute the value of x from b in a

⇒$4(y+2)-32 =y$

⇒$4y+8-32 =y$

⇒$4y-24 =y$

⇒$3y=24$

⇒$y=\frac{24}{3}$

⇒$y=8$

Now put this value of y in b to get value of x

⇒x-2=8

⇒x=10

Thus the numbers are 10 and 8