If Fs(s), Gs(s) are the Fourier sine transforms of f(x) and g(2) respectively,then I f()g()dx =
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Answer:
-cosx.sin2 + c
Step-by-step explanation:
f(x)=sinx and g(2)=sin2
now,
| f(x)g(2)dx = | sinx.sin2dx = -cosx.sin2 +c.
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